Math, asked by manojchinthapalli, 6 months ago

Find the zeros of the given quadratic polynomials,
(i) p(x) = 3x²-9x+6 = 0.

(P) ½,5 (or) 5,½
(Q) 2,1 (or) 1,2
(R) -1,2 (or) 2,-1
(S) none of these
__________________________
(ii) p(x) = 9x²+12x+3

(P) -1/,-⅓ (or) -⅓,-1
(Q)-1,-1
(R) 1,3 (or) 3,1
(S) none of these​

Answers

Answered by as5434762
1

Step-by-step explanation:

(i) 3x^2-9x+6

3x^2-6x-3x+6

3x(x-2)-3(x-2)

(3x-3)(x-2)

x=1,2

option (Q)

(ii) 9x^2+12x+3

9x^2+9x+3x+3

9x(x+1)+3(x+1)

(9x+3)(x+1)

x=-3/9,-1

x=-1/3,-1

option (P)

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