Question

find the zeros of the p(x)
$p{x} = {x}^{3} + {4x}^{2} - 9x - 36$
if two zeroes of the polynomial are equal in magnitude but opp. in sign

Answer 1

Hey user

Here is your answer :-

x^3 + 4x^2 - 9x - 36 = 0

》x^2 ( x + 4 ) - 9 ( x + 4 ) = 0

》( x + 4 )( x^2 - 9 ) = 0

》( x + 4 )[ ( x )^2 - ( 3 )^2 ] = 0

》( x + 4 )( x - 2 )( x + 2 ) = 0

》x + 4 = 0 or x - 2 = 0 or x + 2 = 0

》x = - 4 or x = 2 or x = - 2

Thank you