find the zeros of the p(x)=x^2-2x-8 and verify that relationship between zeros and coefficient
nandika78:
nice
Answers
Answered by
3
Here is ur answer :
p (x) = x^2 -2x - 8
Let,
p (x)=0
.
. . x^2 - 2x -8=0
.
. . x^2-4x+2x-8=0
.
. . x (x-4)+2 (x-4)=0
.
. . (x-4)(x+2)=0
.
. .x-4=0 & x+2=0
.
. . x=4 x=-2
Here,
Alpha =4, Beta =-2
Here ,
a=1,b=-2,c=-8
Verification :
alpha + beta = 4+(-2)
=4-2
= 2/1
=-b/a
alpha beta = (4)×(-2)
= -8/1
= c/a
Hope it's help u mark on brainlist ☺ ☺
Similar questions