find the zeros of the polinomial 4ksquare+8k
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Answered by
2
Let one zero of quadratic polynomial be x
Other zero =-x
Sum of zeroes=-b/a
x-x=8k/4
0=8k/4
k=0
Answered by
8
4k^2+8k
#taking 4k common,
we get,
4k(k+2)
4k=0 k+2=0
k=0 k=-2
two zeros are
0 and -2
#taking 4k common,
we get,
4k(k+2)
4k=0 k+2=0
k=0 k=-2
two zeros are
0 and -2
RSAshwaniRao:
there is not 2 that is in -2
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