Question

find the zeros of the polnomials x²-7 ​

Answer 1

The zero of the polynomial is,

x²-7=0

x²=7

x=√7

So the zero of the polynomial is √7....

Answer 2

${x}^{2} - 7 \\ we \: can \: also \: write \: as \\ {x}^{2} - { \sqrt{7} }^{2} \\ we \: will \: use \: the \: identity \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ (x + \sqrt{7} )(x - \sqrt{7} ) \\ roots \\ x + \sqrt{7} = 0 \\ x = - \sqrt{7} \\ x - \sqrt{7} = 0 \: x = \sqrt{7}$