Find the zeros of the polynomiaand verify the relationship 2x3 +x2 -13x + 6
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here is the your Ans
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put the factor value of 6 is 2
X =2
2(2)^2 +(2)^2 -13×2 +6
2×8 + 4 -26 +6
16+4 -26 +6
26-26 =0
so
(x-2) is a factor of the equation
2x^2(x-2) +5x(x-2) -3(x-2)
=> (x-2) (2x^2 +5x-3)
=> (x-2) (2x^2 +3x+2x -3)
=> (x-2) {x( 2x+3) -1( 2x+3) }
=> [(x-2) (x-1) ( 2x+3) ] Ans
hope it's helpful for you ✌☺
========================================
put the factor value of 6 is 2
X =2
2(2)^2 +(2)^2 -13×2 +6
2×8 + 4 -26 +6
16+4 -26 +6
26-26 =0
so
(x-2) is a factor of the equation
2x^2(x-2) +5x(x-2) -3(x-2)
=> (x-2) (2x^2 +5x-3)
=> (x-2) (2x^2 +3x+2x -3)
=> (x-2) {x( 2x+3) -1( 2x+3) }
=> [(x-2) (x-1) ( 2x+3) ] Ans
hope it's helpful for you ✌☺
Natasha77:
Verify the relationship
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