find the zeros of the polynomial :- 1) 3x²-x-4. and x represents the letter x, not multiplication
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Answered by
15
3x^-x-4=0
3x^-4x+3x-4=0
3x^+3x-4x-4=0
3x(x+1)-4(x+1)=0
(3x-4)(x+1)=0
3x-4=0 3x=4 x=4/3
x+1=0 x=-1
3x^-4x+3x-4=0
3x^+3x-4x-4=0
3x(x+1)-4(x+1)=0
(3x-4)(x+1)=0
3x-4=0 3x=4 x=4/3
x+1=0 x=-1
mp3:
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Answered by
24
3x² - x - 4
= 3x² + 3x - 4x - 4
= 3x(x+1) -4(x+1)
= (3x - 4 )(x + 1)
Zeros are -
• 3x - 4 = 0
x = 4/3
• x + 1 = 0
x = -1
= 3x² + 3x - 4x - 4
= 3x(x+1) -4(x+1)
= (3x - 4 )(x + 1)
Zeros are -
• 3x - 4 = 0
x = 4/3
• x + 1 = 0
x = -1
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