Question

find the zeros of the polynomial 100xsquare - 81

Answer 1

$100 {x}^{2} - 81 = 0 \\ {(10x)}^{2} - {9}^{2} = 0 \\ (10x + 9) \times (10x - 9) = 0 \\ x = - \frac{9}{10} \\ x = \frac{9}{10}$
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Answer 2

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