Question

find the zeros of the polynomial 12xsquare-7x+1​

Answer 1

Answer:

the

Step-by-step explanation:

12x²-7x+1=0

12x²-4x-3x+1=0

4x(3x-1)-1(3x-1)=0

(4x-1)(3x-1)=0

4x=1

X=1/4

and

3x=1

X=1/3

I HOPE U MAY understand

Answer 2

Answer:

x = 1/3 or x= 1/4

Step-by-step explanation:

12 x^2 -7x +1

= 12 x^2 -(4x+3x)+1 =0

= 12 x^ 4x -3x +1 =0

4x (3x-1) -1 (3x-1) = 0

(3x-1) ( 4x -1)

3 x-1= 0 4 x -1 =0

3x = 1 4x = 1

x = 1/3 x= 1/4

Hence the zeroes of quadratic equation are :

1 /3 & 1/4