Question

Find the zeros of the polynomial 2 √3 x2 – 5x + √3 and
verify the relation between the zeroes and the Coefficients?


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Answer 1

Step-by-step explanation:

Let f(x) = 2 √3 x2 – 5x + √3

= 2 √3 x2 – 2x – 3x + √3

= 2x(√3x-1) – √3(√3x-1)

To find the zeroes,

set f(x) = 0 (√3x – 1) or (2x – √3) = 0 x = 1/√3 = √3/3 or x = √3/2 x = √3/3 or x = √3/2

Again,

Sum of zeroes = √3/3 + √3/2 = 5√3/6 = -b/a = (-Coefficient of x)/(Cofficient of x2)

Product of zeroes = √3/3 x √3/2 = √3/6 = c/a = Constant term / Coefficient of x2