Question

find the zeros of the polynomial 2 x2 + 3 x = 9 verify the relationship between the zero and the coefficient​

Answer 1

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Answer 2

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2x² +3x = 9

2x² +3x -9 = 0

2x² +(6-3)x -(6×3) = 0

2x² +6x -3x -9 = 0

2x(x+3) -3(x+3) = 0

(2x-3)(x+3) = 0

So x = 3/2 and -3

Relationship between the zeroes and the co efficient is:--

3/2 +(- 3) => 3-6/2 => -3/2 = -(coefficient of x)/(coefficient of x ²)

3/2×3 = 9/2 = constant term/coefficient of x ²..

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