find the zeros of the polynomial 2 y square -32 is equal to 0
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and
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Given polynomial :
2y²-32=0
Taking 32 on right side as the polynomial is incomplete.
→2y²=32
→y²=32/2
→y²=16
→y=±√16
→y=±4 ( required answer )
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Hence, the zeroes of this polynomial ( 2y²-32=0 ) is (-4) and (4).
Answered by
0
2y^2-32=0
2y^2=32
y^2=16
y=4 and y=-4
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