find the zeros of the polynomial 2x^2-9 and verify the relationship between the zeros and the coefficient
Answers
Answered by
2
Step-by-step explanation:
First of all split the middle term and it will be in this form
2x^2+6x-x-3
take common
2x(x+3)-1(x+3)
(2x-1)(x+3)
x=1/2 , -3
Verification
let alpha and beta be the zeroes of the polynomial
alpha=1/2 and beta=-3
alpha+beta=-b/a
1/2+(-3)=-5/2
-6+1/2=-5/2
-5/2=RHS
and alpha×beta=c/a
1/2×-3=-3/2
-3/2= RHS
hence, verified
Hope it helps you and thanks for reading!
Answered by
0
Step-by-step explanation:
2x^2=9
x1=3/root2
x2=-3/root2
x1+x2=-b/a=0
x1×x2=9/2
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