Question

find the zeros of the polynomial 2x square + 9 x - 35​

Answer 1

2x² + 9x - 35

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 9 \frac{ + }{} \sqrt{81 + 4 \times 2 \times 35} }{2 \times 2} \\ x = \frac{ - 9 \frac{ + }{} \sqrt{361} }{4} = \frac{ - 9 \frac{ + }{} 19}{4} \\ \\ x = \frac{ - 9 + 19}{4} = \frac{10}{4} = \frac{5}{2} \\ x = \frac{ - 9 - 19}{4} = \frac{ - 28}{4} = - 7$

Therefore,

$2 {x}^{2} + 9x - 35 = (x - \frac{5}{2} )(x - ( - 7)) \\ = ( x - \frac{5}{2} )(x + 7)$

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Answer 2

Step-by-step explanation:

$2 {x}^{2} + 9x - 35 = 0 \\ 2 {x }^{2} + 9x = 35 \\ 9x = 35 - 2 {x}^{2} \\ x = (35 - 2 {x}^{2} ) \frac{1}{9}$

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