Question

Find the zeros of the polynomial

Answer 1

Hey user here is your answer

Answer 2

Hii !!

f(x) = x² - (√3 + 1)x + √3

f(x ) = x² - √3x - x + √3 = 0

f(x) = x( x - √3) - 1 ( x - √3 ) = 0

f(x) = (x - 1) (x - √3) =0

x - 1 = 0

x = 1

and x - √3 = 0

x = √3

so f(x) = f(1) and f(-√3)

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let's verify it

f(1) = 1² - (√3 + 1) 1 + √3

f(1) = 1 - √3 - 1 + √3

f(1) = 0

and similarly

f( √3) = (√3)² -( √3 - 1 ) √3 + √3

f( √3) = 3 - 3 - √3 + √3

f ( √3 ) = 0

hence , my both answer is verified thou

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Hope it helps you !!!

@Rajukumar111
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