Find the zeros of the polynomial 3x cube + x-2
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Answer:
3x^2 + x - 2 = 0
( 3x^2 + 3x ) ( -2x - 2)=0
3x(x + 1) -2 (x+1) =0
(3x -2) (x+1) =0
3x -2 = 0
3x = 2
x = 2/3
x+1=0
x = -1
thereby, 2/3 and -1 are the zeros of the polynomial.
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