Question

find the zeros of the polynomial 4 x square + 8 x​

Answer 1

Answer:

4x"2+8x

2x(2x+4)

2x=0. 2x+4=0

x= -2, x= -4/2

therefore x= -2. x= -2

thus zero is quadratic polynomial

4x"2+8x= -2, -2

here is ur answer

Answer 2

$\huge{ \underline{ \boxed{ \sf{ \blue{AnsweR :}}}}}$

• We have to find the zeroes of the polynomial.
• The polynomial is 4x² + 8x

⟹ 4x² + 8x

Taking 2x common,

⟹ 2x ( 2x + 4 )

Making 2x equal to zero in order to find the value of x,

⟹ 2x = 0

Taking 2 to the other side,

⟹ $\boxed{x = 0}$

Now making ( 2x + 4 ) equal to zero,

⟹ 2x + 4 = 0

Taking 4 to the other side,

⟹ 2x = - 4

Taking 2 to the other side,

⟹ $x = \frac{ - 4}{2}$

⟹ $\boxed{x = - 2}$

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$\boxed{ \sf{ \red{VerificatioN}}}$

Let us verify if our answer is right by substituting the value of x in the given polynomial. If the whole answer is 0, it means that our answer is perfectly right.

When x = 0,

⟹ 4 ( 0 )² + 8 ( 0 )

⟹ 0

When x = -2,

⟹ 4 ( -2 )² + 8 ( -2 )

⟹ 16 - 16

⟹ 0.

Hence, 0 and -2 are the zeroes of the polynomial 4x² + 8x.

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Thanks for the question ;)