Question

find the zeros of the polynomial 4 y square - 4 Y + 1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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• The given equation : 4y² - 4y + 1

We can find the zeroes of the given polynomial by using the method

splitting the middle term.

⟹ 4y² - 4y + 1

⟹ 4y² - 2y - 2y + 1

Taking 2 as common & taking - 1 as common we get,

⟹ 2y ( 2y - 1 ) - 1 ( 2y - 1 )

Now,

⟹ ( 2y - 1 ) ( 2y - 1 )

In order to find the value of y, we should make the equation equal to 0.

⟹ 2y - 1 = 0

⟹ 2y = 1

⟹ y = $\frac{1}{2}$

Repeating the same thing,

⟹ 2y - 1 = 0

⟹ 2y = 1

⟹ y = $\frac{1}{2}$

So, the zeroes of the given polynomial are $\frac{1}{2}\:and\:\frac{1}{2}$

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