Question

Find the zeros of the polynomial 49x2-64​

Answer 1

Answer:

x = - 8/7 and x = 8/7

Step-by-step explanation:

Given : 49x² - 64

We know that, 49 is the square of 7 and 64 is the square of 8.

Therefore,

We can write this as :

→ (7x)² - (8)²

Identity : a² - b² = (a + b)(a - b)

Here, a = 7x, b = 8

→ (7x + 8)(7x - 8)

To find the zeroes, we have to use zero product rule.

→ (7x + 8) = 0 and (7x - 8) = 0

→ x = - 8/7 and x = 8/7

Hence, the zeroes are - 8/7 and 8/7.

Other identities which are frequently used :

• (a + b)² = a² + 2ab + b²

• (a - b)² = a² - 2ab + b²

• (a + b)² - (a - b)² = 4ab

Answer 2

Answer:

x = -8/7 [OR] x = 8/7

Step-by-step explanation:

To find zero of polynomial,p(x)=0

49x²-64 = 0

(7x)²-8² = 0

(7x+8)(7x-8) = 0

So either (7x+8) = 0 [OR] (7x-8) = 0

Therefore x = -8/7 [OR] x = 8/7