Question

Find the zeros of the polynomial 4u^2+8u

Answer 1

Answer:

Step-by-step explanation:

let p(X)-4u^2+8u

p(1)=4(1)^2+8(1)|

=4+8

=12

Answer 2

Answer:

4u2 + 8u = 0

4u ( u+8)=0

4u =0 u+8=0

u=0 u= -8

zeroes of the polynomial = 0,-8