Math, asked by sahil26082004, 1 year ago

Find the zeros of the polynomial 4u^2+8u

Answers

Answered by lovlyzarah
0

Answer:

Step-by-step explanation:

let p(X)-4u^2+8u

p(1)=4(1)^2+8(1)|

=4+8

=12


sahil26082004: Answer is wrong
Answered by mehak5019
5

Answer:

4u2 + 8u = 0

4u ( u+8)=0

4u =0 u+8=0

u=0 u= -8

zeroes of the polynomial = 0,-8

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