Find the zeros of the polynomial 4u^2+8u
Answers
Answered by
0
Answer:
Step-by-step explanation:
let p(X)-4u^2+8u
p(1)=4(1)^2+8(1)|
=4+8
=12
sahil26082004:
Answer is wrong
Answered by
5
Answer:
4u2 + 8u = 0
4u ( u+8)=0
4u =0 u+8=0
u=0 u= -8
zeroes of the polynomial = 0,-8
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