Find the zeros of the polynomial 4x2 – 3x– 1 by factorization method and verify the
relations between the zeros and the coefficients of the polynomial
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Answer:
Let f(x)=4x2−3x−1
Splitting the middle term, we get
=4x2−4x+1x−1
=4x(x−1)+1(x−1)
=(x−1)(4x+1)
For f(x)=0, we have
4x2−3x−1=0
or (x−1)(4x+1)=0
Either x−1=0⇒x=1
or 4x+1=0
⇒4x=−1
⇒x=4−1
∴ The zeroes of f(x) are 1 and 4−1.
Verification:
α=1,β=4−1
a=4,b=−3 and c=−1
∴α+β=a−b
⇒1−41=4−(−3)
⇒43=
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