find the zeros of the polynomial
4x² + 5x + 1
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x = -1 & -1/4
Step-by-step explanation:
4x² + 5x + 1 = 0
=> 4x² + 4x + x + 1 = 0
=> 4x (x + 1) + 1 (x + 1) = 0
=> (x + 1)(4x + 1) = 0
So,
zero no. 1-
x + 1 = 0
=> x = -1
zero no. 2 -
4x + 1 = 0
=> 4x = -1
=> x = -1/4
Hence zeroes are -1 & -1/4
hope it helps.
#BeBrianly :)
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