Math, asked by wilsonmascarenhas200, 8 months ago

find the zeros of the polynomial 4x²+7x-2​

Answers

Answered by prince5132
17

GIVEN :-

  • p(x) = 4x² + 7x - 2.

TO FIND :-

  • The zeros of p(x).

SOLUTION :-

☛ We have to find the zeros of the polynomial so, p(x) = 0.

ACCORDING TO QUESTION,

➫ p(x) = 0

➫ 4x² + 7x - 2 = 0

➫ 4x² + 7x - 2 = 0

➫ 4x² + 7x -2 = 0

➫ 4x² - x + 8x - 2 = 0

➫ x(4x - 1) + 2(4x - 1) = 0

➫ (4x - 1) , (x + 2) = 0

➫ 4x - 1 = 0 , x + 2 = 0

➫ 4x = 1 , x = -2

x = 1/4 , x = -2

Hence the zeros of p(x) are 1/4 and (-2).

Answered by Anonymous
26

ANSWER

\large\underline\bold{GIVEN,}

\sf\dashrightarrow 4x^2+7x-2

\large\underline\bold{TO\:FIND,}

\sf\dashrightarrow \:ZEROES\:OF\:THE\:POLYNOMIAL.

ACCORDING TO THE QUESTION,

\sf  {\boxed{\bf{\:\: to\:find\:zeroes\:of\:the\:polynomial\:we\:need\:p(x)=0}}}

\large\underline\bold{SOLTUION,}

\sf\implies  4x^2+7x-2=0

\sf\implies  4x^2+8x-x-2=0

\sf\implies 4x(x+2)-1(x+2)=0

\sf\implies (4x-1)(x+2)=0

\sf\implies 4x-1=0 ,x+2=0

\sf\implies 4x=1,x=-2

\sf\implies x= \dfrac{1}{4},x=-2

\sf\implies x= \dfrac{1}{4},-2

\large{\boxed{\bf{ \star\:\:x= \dfrac{1}{4},-2\:\: \star }}}

\large\underline\bold{THE\:ZEROES\:OF\:THE\:POLYNOMIAL\:ARE\: \dfrac{1}{4},-2}

___________________

Similar questions