find the zeros of the polynomial 5x2 +12x+7 and verify the relationship between the zeros and their coefficients.
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Answered by
35
here it is!!!!
=】5x^2+12x+7
=】5x^2+5x+7x+7
=】5x(x+1)+7(x+1)
=】(5x+7)(x+1)
so there fore zeroes are x=-1,-7/5
NOW verifications
so
sum of zeroes = -b/a
=】-1+(-7/5)=-12/5
=】-12/5=-12/5
LHS=RHS
now
product of zeroes!!!!
product =c/a
(-1)(-7/5)=7/5
7/5=7/5
LHS=RHS
hence showed!!!!!!!!!!
HOPE this HELP!!!!!!!
=】5x^2+12x+7
=】5x^2+5x+7x+7
=】5x(x+1)+7(x+1)
=】(5x+7)(x+1)
so there fore zeroes are x=-1,-7/5
NOW verifications
so
sum of zeroes = -b/a
=】-1+(-7/5)=-12/5
=】-12/5=-12/5
LHS=RHS
now
product of zeroes!!!!
product =c/a
(-1)(-7/5)=7/5
7/5=7/5
LHS=RHS
hence showed!!!!!!!!!!
HOPE this HELP!!!!!!!
Answered by
9
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