find the zeros of the polynomial 6 root 5 x square - 9 x minus 3 root 5
Answers
Answered by
0
Answer:√5/2 and -√5/5
Step-by-step explanation:
We know D = b^2 - 4ac (D is DISCRIMINANT)
=> 81 - 4 X 6√3 X (-3√5)
=> 81 + 360
=> 441
x = (-b +-√D)/2a
=> (9 + 21)/12√5 and (9 - 21)/12√5
=> 10/4√5 and -1/√5
On rationalising the denominator we get our answer.
Hope it helps
Similar questions