Question

find the zeros of the polynomial 6 x cube - 11 x + 12 if x-1 is a factor of the polynomial​

Answer 1

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Answer 2

Solution==>>

p(x)=6x³-7x²-11x+12=0

give that x-1 is a factor of p(x)

so, x-1=0

x=1

now put value of x in p(x)

6x³-7x²-11x+12=0

6(1)³-7(1)²-11(1)+12=0

6-7-11+12=0

-7-11+6+12=0

-18+18=0

0

Therefore, another zero of p(x) is 0.

Answer........