Question

find the zeros of the polynomial 6x^2 -13x -8. also verify the relation between zeros and coefficients​

Answer 1

Answer:

$x = \frac{8}{3} \: or \: \frac{ - 1}{2}$

I will tell you how it came.

Step-by-step explanation:

$6 {x}^{2} - 13x - 8 = 0 \\ 6 {x}^{2} - 16 x + 3x - 8 = 0 \\ 2x(3x - 8) + 1(3x - 8) = 0 \\ (3x - 8)(2x + 1) = 0 \\ x = \frac{8}{3} \: or \: \frac{ - 1}{2}$

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