Question

Find the zeros of the polynomial 6x^2-3

Answer 1

Answer:

+-1/^2 is the answer

Step-by-step explanation:

6x^2-3=0

6x^2=3

x2=3/6

x2=1/2x=√1/2

Sox=+ and

-1/√2

Answer 2

Answer:

Step-by-step explanation:

For zeros

6x^2-3=0

3(2x^2-1)=0

3{(√2x)^2 -1^2}=0

3(√2x-1)(√2x+1)=0

√2x-1 =0 or √2x+1=0

x= 1/√2 ,-1/√2