Find the zeros of the polynomial 6x square- 7z-3 and verify the relationship between the zeros and the coefficients?
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Step-by-step explanation:
p(x)= 6x^2-7x-3
=6x^2-9x+2x-3
=3x(2x-3)+1(2x-3)
=(3x+1) (2x-3)
alpha(a)= 3x+1=0
=x=-1/3
bita(b)=2x-3=0
=x=3/2
verification between zeros and coefficient are:-
(i) a+b = -b/a
=(-1/3)+(3/2)=7/6
=-2+9/6=7/6
=7/6=7/6
(ii) ab = c/a
=-1/3×3/2=-3/6
= -3/6=-3/6
verified :-
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