Question

Find the zeros of the polynomial 6x square + X - 2 and verify also

Answer 1

solution :

Given:

• a polynomial
• $6 {x}^{2} + x + 2 = 0$

To find: .

• zeros of the polynomial

$6 {x}^{2} + x - 2 = 0 \\ \\ \implies \: 6 {x}^{2} + 4x - 3x - 2 = 0 \\ \\ \implies \: 2x(3x + 2) - 1(3x + 2) = 0 \\ \\ \implies \: (3x + 2)(2x - 1) = 0$

$\therefore \: x = \dfrac{ - 2}{3} \: and \: x = \dfrac{1}{2}$

by substituting the values of X in the polynomial the polynomial becomes zero , therefore it can be verified .