Question

Find the zeros of the polynomial 6x2-17x+7

Answer 1

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Answer 2

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Here is you answer...

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${6x}^{2} - 17x \: + 7 \\ = > \: {6x}^{2} - 3x \: - 14x \: + 7 \\ = > 3x( \: 2x - 1) \: - 7(2x \: - 1) \\ = > \:( 3x - 7)(2x - 1)$
♦ 3x - 7 = 0
=> 3x = 7
=> x = 7/3

♦ 2x - 1 = 0
=>2x = 1
=> x = 1/2

Either x = 7/3 or 1/2.

✴ Hence, zeroes of the polynomial are 7/3 and 1/2.

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