Question

Find the zeros of the polynomial() = 9
²-4.​

Answer 1

Given:

• P(x) = 9x²-4

To Find:

• The zeroes

Solution:

$\sf \: 9 {x}^{2} - 4 = {(3x)}^{2} - {(2)}^{2} \\ \sf \: = (3x - 2)(3x + 2) \\ \sf \: (3x - 2) = 0 \: \: \: \: \: \: or \: \: \: \: \: (3x + 2) = 0 \\ \boxed{\sf \: x = \frac{2}{3}} \: \: \: \: \: \sf \: or \: \: \: \: \: \boxed{ \sf x = \frac{( - 2)}{3} }$

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