Question

Find the zeros of the polynomial and verify the relationship between the zeros and their coefficients: 2u^2 - 7

Answer 1

Answer:

Let f(u) = 4x2 - 7

4u² - 7 = 0

(2u)² - (√7)² =0

Using a2 - b2 = (a - b)(a + b), we have

(2u - √7)(2u + √7) = 0

2u - √7 = 0 or 2u + √7 = 0

2u = √7 or 2u = -√7

u = √7/2 or u = -√7/2

α + β = √7/2 + (-√7/2) = 0 = 0/4 = -b/a

αβ = √7/2*-√7/2 = -7/4 = c/a

So, α + β = -b/a and αβ = c/a

HOPE , IT HELPS ... ✌