find the zeros of the polynomial and verify the relationship between the coefficients and the zeros of 2 x square - 9
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Answer:
2x²- 9 = 0
2x² - (√9)² = 0
(2x - √9) (2x +√9) = 0
2x - √9 = 0. 2x +√ 9 =0
2x - 3 = 0 2x + 3 =0
2x = 3. 2x = -3
x = 3/2 x= -3/2
Sum of the zeroes = - b/a
alpa + beta = -0/2
3/2 - 3/2 = 0
0 =. 0
Product of the zeroes = c/a
alpa(beta) =. -9/2
3/2(-3/2) = -9/2
-9/2. = -9/2
I hope it will help you mate!
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