Question

Find the zeros of the polynomial and verify the relationship between zeros and its coefficient. p(x)= x^2+2√2x-6​

Answer 1

Hey Mate

Here Is Your Answer

$px = {x}^{2} + 2 \sqrt{2} x - 6 \\ \: \: \: \: \: \: = ({x}^{2} - \sqrt{2} x)(3 \sqrt{2} x - 6) \\ \: \: \: \: \: \: = x(x + \sqrt{2} ) + 3 \sqrt{2} (x + \sqrt{2} ) \\ \: \: \: \: \: \: = (x + \sqrt{2} )(x + 3 \sqrt{2} ) \\ \: \: \: \: \: \: = x + \sqrt{2} = 0 \: \: \: x + 3 \sqrt{2} = 0 \\ \: \: \: \: \: \: = x = - \sqrt{2} \: \: \: \: \: \: \: \: \: \: x = - 3 \sqrt{2}$

Hope It Will Help

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GUNJAN