Question

find the zeros of the polynomial and verify the relationship between the zeros and their cofficients of
${x}^{2} - 10x + 25$
​

Answer 1

Step-by-step explanation:

zeros of the polynomial

x^2-10x+25

x^2-5x-5x+25

X(x-5)-5(x-5)

(x-5) (x-5)

therefore zero of the polynomial is 5

relation

sum of the zeros =. -( cofficient of x,)/cofficient of x^2

-10/1=-10

product of the zeros=constant term /cofficient of x^2

=25/1=25