Math, asked by Anonymous, 11 months ago

Find the zeros of the polynomial and verify the relationship between the zeros and coefficients t square - 3


Anonymous: ___k off

Answers

Answered by rudra09
5

See the attachment....... hope its help u

Attachments:

Anonymous: wello
Answered by ShiningSilveR
3

hey mate here's ur answer

given \: polynomial \:  =  \: t ^{2}  - 3 \\  = t {}^{2}  - ( \sqrt{3} )^{2}  \\  = (t -  \sqrt{3})(t +  \sqrt{3} ) \\   \\ either \: t -  \sqrt{3}  = 0 \: or \: t +  \sqrt{3}  = 0 \\  =  > t \:  =  \:   \sqrt{3}  \: or \:  -  \sqrt{3}  \\

we know that

sum of zeroes = √3 - √3 = 0 = -b/a

product of zeroes = √3 × - √3 = - 3 = c/a

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