Question

Find the zeros of the polynomial f(m)=m^2+m-156

Answer 1

Answer:

12. -13

Step-by-step explanation:

f(m)=m^2+m-156

m^2+m-156 =0

m^2 + 13m - 12m -156 =0

m(m+13) -12(m+13) =0

(m-12) (m+13) =0

(m-12) =0 (m+13)=0

m=12. m=(-13)

Therefore, m=12.(-13)

Answer 2

Answer :-

• m² + m - 156

=> m² + 13m - 12m - 156

=> m (m + 13) - 12 (m + 13)

=> (m - 12) (m + 13)

=> m = 12, - 13