find the zeros of the polynomial f of x is equal to root 3 X square + 5 x minus 8 root 3 and verify the relationship between the zeros and its coefficient
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√3x^2 + 5x - 8√3 = 0
√3x^2 + 8x - 3x - 8√3 = 0
x(√3x+8) - √3(√3x+8) = 0
(√3x+8) ( x-√3) = 0
x = -8/√3 , √3
Sum of the zeroes = -8/√3 + √3 = -5/√3
-5/√3 = -5/√3
Product of the zeroes = -8/√3 × √3 = -8√3/√3
-8 = -8
Answered by
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√3x^2+5x-8√3 =0
√3x^2+8x-3x-8√3=0
x(√3x+8)-√3(√3x+8)=0
(√3x+8)(x-√3)=0
x=-8/√3,√3
Sum of the zeroes= -8/√3+√3=-5/√3
= -5/√3=-5/√3
Product of the zeroes=-8/√3×√3=-8√3/√3-8=-8.... ..........
Hope it helps you. ......
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