Math, asked by sarlawankhede123, 11 months ago

find the zeros of the polynomial f of x is equal to root 3 X square + 5 x minus 8 root 3 and verify the relationship between the zeros and its coefficient​

Answers

Answered by Anonymous
3

3x^2 + 5x - 83 = 0

3x^2 + 8x - 3x - 83 = 0

x(3x+8) - 3(3x+8) = 0

(3x+8) ( x-√3) = 0

x = -8/3 , 3

Sum of the zeroes = -8/3 + 3 = -5/3

-5/3 = -5/3

Product of the zeroes = -8/3 × 3 = -83/3

-8 = -8

Answered by ItzAaryan
2

3x^2+5x-83 =0

3x^2+8x-3x-83=0

x(3x+8)-3(3x+8)=0

(3x+8)(x-√3)=0

x=-8/3,3

Sum of the zeroes= -8/3+3=-5/3

= -5/3=-5/3

Product of the zeroes=-8/3×3=-83/3-8=-8.... ..........

Hope it helps you. ......

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