Question

Find the zeros of the polynomial f(t)=t^2-15 and verify the relationship between the zero and their coefficient

Answer 1

f(t) = t^2-1

Step-by-step explanation:

t = ✓15 Verify yourself it's an easy questions

Answer 2

ANSWER:

• Zeros are √15 and (-√15).

GIVEN:

• F(t) = t²-15

TO VERIFY:

• Relationship between the zeros and coefficients.

SOLUTION:

Finding zeros:

=> t²-15 = 0

=> (t)²-(√15)² = 0

=> (t-√15)(t+√15) = 0

Either (t-√15) = 0

=> t= √15

Either (t+√15) = 0

=> t = (-√15)

Here:

=> α = √15

=> β = -√15

Formula:

=> Sum of zeros (α+β) = -(Coefficient of x)/Coefficient of x²

=> Product of zeros (αβ) = Constant term/ Coefficient of x²

=> α+β = -√15+√15

=> α+β = 0/1

=> -(-0)/1 = -(Coefficient of x)/Coefficient of x²

=> αβ = -(√15)(√15)

=> αβ = -15

=> -15/1 = Constant term/ Coefficient of x²