Question

Find the zeros of the polynomial f(x) = 4x2+8x

Answer 1

4x²+8x
x(4x+8)
Factors of 8 ±1±2±4±8
Let f(x)=1
(4+8)=12x≠0
Let f(x)=-1
-4+8=4≠0
Let f(x)=2
8+8=16≠0
Let f(x)=-2
-8+8=0
:. (X+2) is a factor.
Now dividing (4x²+8x) by (x+2)
=4x(x+2) Factor

:. Zeroes=-2(ANSWER)

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Answer 2

4*2+8x=>8+8x=0
8x=-8
X=-8/8=-1