Question

Find the zeros of the polynomial F(x)=square+7x+12

Answer 1

[tex] {x}^{2} + 7x + 12 = 0 \\ {x}^{2} + 4x + 3x + 12 = 0 \\ x(x + 4) + 3(x + 4) = 0 \\ (x + 4)(x + 3)
X=-4,-3
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Answer 2

f(x) = x² + 7x + 12

x² + 7x + 12 = 0
x² + 4x + 3x + 12 = 0
x(x+4) + 3(x+4) = 0
(x+4) (x+3) = 0

→ x+4 = 0
x = -4

→ x+3 = 0
x = -3

-4 and -3 are zeroes of the polynomial