Question

Find the zeros of the polynomial f(x)=x^3-5x^2-16x+80

Answer 1

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Answer 2

Answer:

the zeros are 4, -4, 5

Step-by-step explanation:

x^3 - 5x^2-16x+80

=x^2(x-5) - 16(x-5)

=(x^2 - 16) (x-5)

=(x^2 - 4^2) (x-5)

=(x+4) (x-4) (x-5)

therefore the zeroes are 4, -4, 5