find the zeros of the polynomial f(x)=x^3 -9x^2+26x-24,if it is given that sum of its two zeros is 5.
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let the zeroes be a, b, and c
and a+ b = 5 ( given)
a+ b+ c = 9
c = 4
ab + bc + ca = 26
ab + c(a+b) = 26
ab = 6
(a - b)^2 = (a +b)^2 - 4ab
(a - b)^2 = 1
(a - b) = 1
since a +b = 5 and a -b = 1
we get a= 3 and b= 2
Hence, the required zeroes are 2, 3 and 4
Hope it helps!!!!!
and a+ b = 5 ( given)
a+ b+ c = 9
c = 4
ab + bc + ca = 26
ab + c(a+b) = 26
ab = 6
(a - b)^2 = (a +b)^2 - 4ab
(a - b)^2 = 1
(a - b) = 1
since a +b = 5 and a -b = 1
we get a= 3 and b= 2
Hence, the required zeroes are 2, 3 and 4
Hope it helps!!!!!
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