Question

find the zeros of the polynomial f(x) =x^-3x-28 and verify the relationship between the zeros and the cofficients​

Answer 1

Step-by-step explanation:

x² −3x−28=0

x² −7x+4x−28=0

x(x−7)+4(x−7)=0

(x+4)(x−7)=0

∴x=−4,7

sum of roots=−4+7=3

product of roots=−4×7=−28