find the zeros of the polynomial f(x)=x³- 5x²-2x+24 what it's at given product of two zeros is 12 , -2
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Let α,β and y be the zeros of polynomial f(x) such that ab=12
We have, α+β+y=
a
−b
=
1
−(−5)
=5
αβ+βy+yα=
a
c
=
1
−2
=−2 and αβy=
a
−d
=
1
−24
=−24
Putting αβ=12 in αβy=−24, we get
12y=−24 ⇒ y=−
12
24
=−2
Now ,α+β+y=5 ⇒ α+β−2=5
⇒ α+β=7 ⇒ α=7−β
∴αβ=12
⇒(7−β)β=12 ⇒
7β−β
2
=12
⇒β
2
−7β+12=0 ⇒ β
2
−3β−4β+12=0
⇒β=4 or β=3
∴α=3 or α=4
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