Question

find the zeros of the polynomial f(y) = 4y^2 -4y +1​

Answer 1

Answer:

f(y)=0

4y²-4y+1=0

4y²-2y-2y+1=0

(4y²-2y)-(2y+1)=0

2y(2y-1)-1(2y-1)=0

(2y-1)(2y-1)=0

(2y-1=0)(2y-1=0)

y=½ and y=½

Therefore, the zeros of the polynomial are ½ and ½.