Question

find the zeros of the polynomial function f(x) =4x^2_25​

Answer 1

Answer:

$x = \frac{5}{2} \: and \: - \frac{5}{2} \: are \: zeroes \: of \: the \:$

$polynomial$

Step-by-step explanation:

$4 {x}^{2} - 25 = 0 = > (2x - 5)(2x + 5)$

$= 0 = > 2x + 5 = 0 \: or \: 2x - 5 = 0$

$= > x = \frac{5}{2} \: or \: \frac{ - 5}{2} .$

Answer 2

Answer:

(2x)^2 - 5^2

(2x+5)(2x-5)

zeros

x=-5/2

x =5/2