Question

find the zeros of the polynomial fx=√3xsquare+10x+7√3 and verify the relationship between the zeroes and coefficient​

Answer 1

√3xsq. +7x+3x+7√3=0

x(√3x+7)+√3(√3x+7)=0

(√3x+7)(x+√3)=0

√3x+7=0

x= -7/√3

x+√3=0

x= -√3

α+β=-b/a

=-10/√3

αβ=c/a

=7√3/ √3

Answer 2

Answer:

Step-by-step explanation:

√3xsq. +7x+3x+7√3=0

x(√3x+7)+√3(√3x+7)=0

(√3x+7)(x+√3)=0

√3x+7=0

x=-7/√3

x+√3=0

x=-√3

α+β=-b/a

=-10/√3

αβ=c/a

=7√3/√3