Question

find the zeros of the polynomial in g(x)=5t^2-20 t (ans fast n show claculation)

Answer 1

g(x) = 5t^2 -20 = 5(t^2-4)

For g(x) to be zero,

t^2 - 4 = 0

=> t = ± 2

Therefore zeroes of g(x) are 2 and -2

Answer 2

Step-by-step explanation:

g (x)= 5t^2-20=5 (t^2-4)

for g(x) to be zero

t^2-4=0

so,t=+2